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Discriminant Quick Reference

Examples

Example 1: Two Distinct Real Roots

Equation: x² - 5x + 6 = 0
  a = 1, b = -5, c = 6

Step 1 — Compute discriminant:
  Δ = b² - 4ac = (-5)² - 4(1)(6) = 25 - 24 = 1

Step 2 — Discriminant > 0 → two distinct real roots

Step 3 — Apply quadratic formula:
  x = (-b ± √Δ) / 2a
  x = (5 ± √1) / 2
  x = (5 ± 1) / 2

  x₁ = (5 + 1) / 2 = 3
  x₂ = (5 - 1) / 2 = 2

Roots: x = 3 and x = 2

Factored form: (x - 3)(x - 2) = 0
Vertex: (2.5, -0.25)

Example 2: One Repeated Root (Perfect Square)

Equation: x² - 6x + 9 = 0
  a = 1, b = -6, c = 9

Step 1 — Compute discriminant:
  Δ = (-6)² - 4(1)(9) = 36 - 36 = 0

Step 2 — Discriminant = 0 → one repeated root

Step 3 — Apply formula:
  x = -b / 2a = 6 / 2 = 3

Root: x = 3 (repeated)

Factored form: (x - 3)² = 0
Vertex form: (x - 3)² = 0
Vertex: (3, 0) — parabola touches x-axis at exactly one point

Example 3: Complex Roots (No Real Solutions)

Equation: x² + 2x + 5 = 0
  a = 1, b = 2, c = 5

Step 1 — Compute discriminant:
  Δ = 2² - 4(1)(5) = 4 - 20 = -16

Step 2 — Discriminant < 0 → two complex conjugate roots

Step 3 — Apply formula:
  x = (-2 ± √(-16)) / 2
  x = (-2 ± 4i) / 2

  x₁ = -1 + 2i
  x₂ = -1 - 2i

Roots: x = -1 + 2i and x = -1 - 2i

Geometric meaning: The parabola y = x² + 2x + 5
does not intersect the x-axis (minimum value is 4,
which is above the x-axis).

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